Python is a

Question

Why does the following print only "2"? Doesn't it call A's __init__ method? I expected it to print "1" and then "2" since I thought A's __init__ would be called.

class A:
def __init__(self):
print(1)
class B(A):
def __init__(self):
super(A, self).__init__()
print(2)
obj = B()

Answer 1

Dublicating question..?

anyways, .. for more details.. see answers..
https://www.sololearn.com/discuss/2814302/?ref=app

Answer 2

This is interesting. super(B, self) is kind of same as parameterless super() and gives the expected output.

class A:
def __init__(self):
print(1)

class B(A):
def __init__(self):
super().__init__()
print(2)

obj = B()

But what happens if we use super(A, self) inside class B, like in your example? can we do that ?

Answer 3

this is a great day of the Answering Reality.