return name instead of type

Question

It was meant to return the names , not the types... how to fix it? https://code.sololearn.com/WEeQLqAsWxEF/?ref=app

Answer 1

Replace line 52 with this.

const acceptedPeople = getAcceptedPeople(invitedPeople);

for(person of acceptedPeople){
console.log(person.name);
}

Answer 2

filter function return an array, even if there are only one item found ^^

Answer 3

There are a couple of other ways to approach this too, if you want to change your function to get the accepted people's names and not the person objects.

Method 1 - Reduce:

function getAcceptedPeoplesNames(people) {
return people.filter(canComeToParty).reduce(
(
accumulatedNames,
currentPerson,
index,
peopleList
) => {
const separator = index === peopleList.length -
1 ? "." : ", "
return accumulatedNames + currentPerson.name +
separator
}, "")
}

console.log(getAcceptedPeoplesNames(invitedPeople))

Method 2 - Map & Join:

function getAcceptedPeoplesNames(people) {
return people.filter(canComeToParty).map(person => person.name).join(", ")
}

Then, console log as above.

Answer 4

thank you people!