How to solve the BallPark Order Challange ?

Question

I managed to solve the BallPark Order challenge on my PC yet here in SoloLearn app does not pass the test cases! Any help how could I do it would be appreciated! My code it attached!
https://code.sololearn.com/cNQgbgtWhP4m/?ref=app

Answer 1

order = input() #'Mierda Mierda Mierda Mierda' #input()

list_ord = {'Nachos': 6,
'Pizza': 6,
'Cheeseburger': 10,
'Water': 4,
'Coke': 5}

productos = ['Nachos', 'Pizza', 'Cheeseburger', 'Water', 'Coke']

suma = 0
new_ord = order.split(" ")

for i in new_ord:
if (i in productos) == True:
suma += list_ord.get(i)
else:
suma += list_ord.get('Coke')
print(round(suma*1.07, 2))

Answer 2

a=input()
a=a.split(" ")
sum=0
for i in a:
if i=="Nachos":
sum+=6
elif i=="Pizza":
sum+=6
elif i=="Cheeseburger":
sum+=10
elif i=="Water":
sum+=4
else:
sum+=5
print(round(sum*1.07,2))

Answer 3

Thank You very much Thomas!

Funny, I wrote the exact same code 1h ago and I delete it as it would print the prices separately and not as a total.
Now I realised it was because I did not indent Print () function properly.
Regards,

Answer 4

a=input()
b=a.split()
my_dict= {"Cheeseburger":10, "Water":4, "Coke" : 5, "Nachos": 6, "Pizza": 6}

res=0
for i in b :
if i in my_dict :
res= res+my_dict[i]
else:
res = res + my_dict["Coke"]
sonuc= float(res*1.07)
print(round(sonuc,2))

I've found that, I've missed to "round"

Answer 5

Sometimes, the input string have an \r at the end.

Try adding .strip() to your input (likely the last) and see if that solves the problem.

Answer 6

You will get the input as one String. In the task descriped as:

Input Format
You are given a string of the four items that you've been asked to order that are separated by spaces.

So you can't get it item by item.

Put the whole order in a list. Like this:
order = input(). split()

Answer 7

How do I convert that list [] populated by strings to int(numbers) ?

Answer 8

I managed to solve this on my PC. I get the total for every combination of 4 items. But here in SoloLearn?! I have to do it exactly as the TEST Cases and it doesn't work. Do you have any tips as to how to solve this ?

Answer 9

Yes, include "Nachos"

Answer 10

Fine
Delete the print
Now we make a loop over that list:
sum = 0
for i in order:
if i == 'Nachos'
sum += 6
elif i == 'Coke'
sum += 5
.
.
else:
sum +=5

This added All items.
The last "else" is for the case, the ordered item is not to have.

print(sum) #to check if it works as expected

Answer 11

And next month you will do that with a dict like this
price = {'Nachos':6.00, 'Pizza': 6.00, 'Cheeseburger': 10.00, 'Water': 4.00, 'Coke': 5.00}
It's shorter and a little bit nicer 😉

Answer 12

bit of tip, try using a for loop instead to avoid repeating codes

Answer 13

I think it’s more beautiful to use dictionaries to solve this problem:

menu = {'Nachos': 6,
'Pizza': 6,
'Cheeseburger': 10,
'Water': 4,
'Coke': 5}
order=input()
total = 0
ord= order.split()
for i in ord:
if i in menu:
total += menu[i]
else:
total += menu["Coke"]
print(total+(total*0.07))

It’s crucial to split the input otherwise the output number will be much higher than expected.

Answer 14

x = input().split(" ")
menu = {"Pizza"}
sum = 0
for i in x:
if i=="Pizza":
sum +=6
elif i=="Nachos":
sum +=6
elif i=="Cheeseburger":
sum+=10
elif i=="Water":
sum+=4
else:
sum+=5
fsum = sum + (sum*7)/100
print (fsum)

Answer 15

You have to read the items from the list.
For exsample, if order is your list:
item1 = order[0]
item2 = order[1]
and so on.
And if you have the items, maybe go your way with the cases and prices.

Answer 16

We can do that STEP by STEP if you want.

start with
order = input(). split()
print(order) # to See what we have.
Make input in one line:
Coke Nachos Coke SUBMIT

Do you See the list?

Answer 17

Yes
['Coke', 'Nachos', 'Coke']

Answer 18

You're welcome

Answer 19

I'm still a beginner, so my code was a little longer/ less efficient than some of these others, but here's what worked for me:

#include <iostream>
#include <string>
using namespace std;

void orders(string ordArr[], int size)
{
int f = 0;
for (int i = 0; i < size; ++i)
{
if (ordArr[i] == "Cheeseburger")
f += 10;
else if (ordArr[i] == "Nachos")
f += 6;
else if (ordArr[i] == "Pizza")
f += 6;
else if (ordArr[i] == "Water")
f += 4;
else
f += 5;
}
int subtotal = f;
float tax = subtotal * 0.07;
float total = f + tax;
cout << total << endl;
}
int main()
{
string arr[4] = {"", "", "", ""};
cin >> arr[0] >> arr[1] >> arr[2] >> arr[3];
orders(arr, 4);

return 0;
}

Answer 20

import java.util.HashMap;
import java.util.Scanner;

public class Main {

public static void main(String[] args) {
try {
Scanner scan = new Scanner(System.in);

HashMap<String, Integer> prices = new HashMap<>();
prices.put("Nachos", 6);
prices.put("Pizza", 6);
prices.put("Cheeseburger", 10);
prices.put("Water", 4);
prices.put("Coke", 5);

double finalprice = 0;
String[] input = new String[4];
for (int i = 0; i < input.length; i++) {
String check = scan.next();

if (prices.containsKey(check)) {
input[i] = check;
} else
input[i] = "Coke";

}

for (String h : input) {
prices.containsKey(h);
finalprice += prices.get(h);
}
float tax = (float) ((finalprice * 0.07));
System.out.printf("%,.2f", finalprice + tax);
scan.close();
} catch (Exception t) {
System.out.println("Invalid Input");
}
}
}

//for java users Using HashMap and for Loops this can be done easliy.Hope this helps