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Why True or False ??!!! I don't understand this output for this code, please help me

def is_even(x): if x == 0: return True else: return is_odd(x-1) def is_odd(x): return not is_even(x) print(is_odd(18)) print(is_even(24)) False True

31st Dec 2017, 7:50 PM
Mostafa Haghiri
Mostafa Haghiri - avatar
4 Answers
+ 2
The output is the last two lines True and False. False is the result for print(is_odd(18)). True is the result for print(is_even(24)). I am not sure what you want explained. Below is the explanation for the function calls. Please let me know what line needs more explanation if you don't understand. What does is_even return? 1) if input is 0, it returns True 2) otherwise it returns is_odd(x-1) example: is_even(3) will return whatever is_odd(2) returns What does is_odd return? returns the opposite of is_even(x) example: is_odd(3) will return True because is_even(3) returns False What does is_odd(18) return? 1) opposite of is_even(18) 2) is_even(18) returns is_odd(17) 3) is_odd(17) returns opposite of is_even(17) 4) is_even(17) returns is_odd(16) Continue this and you will understand the code. Happy New Year
31st Dec 2017, 9:41 PM
Sanjay Khanna
0
You can trace it with smaller numbers e.g. 0,1,2,3 0 is_even’s base case= True 0 is_odd returns not is_even(0) = not True=False 1 is_even returns is_odd(1-1)= is_odd(0)=not is_even(0)=not True, which from above= False 1 is_odd = not is_even(1)= not False=True 2 is_even = is_odd(2-1) = is_odd(1)=True 2 is_odd = not is_even(2)= not True= False Basically via is_even it drills down to the base case if the remainder is 1.
31st Dec 2017, 9:21 PM
H Chiang
0
I made a modified code, the output shows in which order the code runs. And I tried to explain with comment: https://code.sololearn.com/c4rOYS5KEZuw/?ref=app
31st Dec 2017, 9:54 PM
Paul
Paul - avatar
0
You know that the answer should be “not not not ~~~ not True” So you only need to count for “not”s. When counting, like in the question: is_even(23) must be changed to “is_odd” (because there is no ‘not’ at the first) —> so it is is_odd(22). Then, you should do —> 22-0+1= 23 odd number of “not”s, equals to one “not” which will then equal to “not True” So the answer is False.
3rd Jan 2018, 5:04 AM
Yololab
Yololab - avatar