i= i++ + ++i - i-- - --i; why the output of this procces is 0?

Question

need answer immediately

Answer 1

step by step
i=5

i++ means i=5 no change(nc)

++i means previous ++ is 5 turn into 6 then again ++ 7 i=7

i-- nc i=7

--i means previous -- is 7 turn into 6 then again -- 5 i=5

5+(7-7)-5
5-5
0

Answer 2

I think that if i=5

i++ in operation 5 is used but i becomes 6
++i is 7
i-- then 7 is used but i becomes 6
--i is 5
so you have 5+7-7-5=0 and when you remove the i-- - --i and run the process i=i++ + ++i; then the result in 5+7=12

Answer 3

what is the initial value of i?

Answer 4

i new in programming but i think:

int y = ++x; // first: increment x, then: assignment
int y = x++ // firsr: assignment, then: increment x

int i = 5;
i = (i++) + (++i) - (i--) - (--i)
// a + b - c - d
a = i++ // a = 5, i = 6
b = ++i // b = 7, i = 7
c = i-- // c = 7, i = 6
d = --i // d = 5, i = 5
// i = 5 + 7 - 7 - 5 = 0

Answer 5

right is

i++ mean no change
++i mean increment
vice versa in -- decrement

its count to right to left not left to right

5+(6-6)-5
5-5
0

Answer 6

mark ur best ans @name

Answer 7

right is

the i=5;

i++ is 5
++i is 7
i-- is 7
--i is 5?

Answer 8

check right
previous was wrong

Answer 9

because its post decrement then stay last value.. and then come pre decrement so it become 5 again ☺

Answer 10

i=(5+5-5-5)+1-1=0
so,the output will be zero
always remember before doing addition or substraction in these kind of problems do preincrement for sure,at the end do the post increment.

Answer 11

its count to right to left not left to right

Answer 12

no problem
love ur community
do some for ur community then better sololearn ☺

Answer 13

sorrt for incompletw question

Answer 14

thanks for the answer guys in understand now :) luv u all

Answer 15

5

Answer 16

i++ is still 5 and ++i will increment to 6?

Answer 17

nice but can i ask u why i-- is 6?

Answer 18

is*

Answer 19

Yeahh i love ur community too .. :)

Answer 20

because when i remove the i-- - --i and the i run the process i=i++ + ++i; then the result in 12