Why is my code not running?

Question

I have started this code, and it looks like this:
var age = 1;

while(age < 7)
age =+ 1;

document.write(age)

But the problem is, it won't show the var "age" when i run the code. It's probably just me missing something totally obvious but i cant figure it out. Anyone?

Answer 1

Write += instead of =+.

Answer 2

There isn't any error message because there isn't any error as far as the interpreter is concerned: your "age=+1;" is being interpreted as "age = +1;" (with the plus as an unary operator. In other words, you were just setting your variable to 1 over and over in your loop.

Answer 3

It doesn't display any error message because you haven't made it to.

In JS you can use:
Try {
alert("Try runs some code and if an error is found the catch does something.");
}
then use

catch {
alert("Catch does something if an error is found.");
}

You can also use

finally
{
alert("This code will always do something even if no error is found.");
}

Explanation:
Try runs the code.
Catch does something if an error is found.
Finally always runs.

For example:

Try {
aler("Note that the t in alert is missing.");
}
Catch {
alert("Error!");
}

Result:
Error!.
I have no idea why SoloLearn didn't include error handling in their courses.

Answer 4

And it also doesnt display any error message

Answer 5

the biggest problem is the format:
while (age < 7){
age += 1;
document.write (age);
}

JS does understand that age is in the while loop

Answer 6

var age = 1;

while(age < 7)
age =age+ 1;

document.write(age)

agora esta corrigido mas tem que adicionar um vento pra funçao funcionar tipo assim:

var age = 1;
function clicked(){
if(age < 7)
age =age+ 1;
}
document.write("<button onclick='clicked()'>click here</button>"+age)

Answer 7

void bot(int mode,string name) {
if(mode==1){
cout<<"Welcome,"<<name<<"!";

}
else if(mode==2){
cout<<"Goodbye,"<<name<<"!";
}
else{
cout<<"Try again";
}
}
Why this is not running it's all correct