What is the output of this code?

Question

int x=4;
int y=6;
sum=x+y;
for (int I=1;I<=10;I++){
sum+=I ; }
System.out.print(sum)

explain me that.. it really bored me

Answer 1

for l=0 sum =sum+l =10+0=10, for l=1, sum=10+1=11,for l=2 ,sum=11+2=13 , for l=3,sum=13+3=16, for every iteration sum is updated with new value

Answer 2

u did not declare sum and l as integers first after declaration u will get 65 as output

Answer 3

It prints the sum of all the numbers from 1 to 11. It's simple...

Answer 4

Ya @rajyalakshmi is correct

Answer 5

first of sum=10 and sum + sum of first 10 integers =10+55= 65

Answer 6

https://code.sololearn.com/cMSiraDxkE2C/?ref=app

Answer 7

sum+=l gives sum=sum+l for every l values from 0 to 10

Answer 8

welcome 😊 all d best for u r bright future

Answer 9

thank you for the remarks.. how do you obtain 65?

Answer 10

if u closed the for loop after print statement u get output as 10,11 etc . for getting 65 for loop closed before print statement

Answer 11

thank you..
let's take another example maybe I will understand , sum+=I equal what?

Answer 12

oooooh thaaaaaaank you!!

Answer 13

for me sum+=I was sum=I+1.. thank you

Answer 14

sum=10 11 12 13 ..20 ; ok.. what is the thing who give 65

Answer 15

you beat me.. it was fun.. thank you.. I will learn the for loop again and I will duel with you :)

Answer 16

look this code:
int i;
for(i=0;i<3;i+=2){}
System.out.print(i);

Answer 17

I=2+0=2;
i=2 now, then I=2+2=4;
I=4 now, then I=2+4=6;
so I=6 finally?

Answer 18

ooooh okaaaaay..