How do I get this to work

Question

If I want the input to be between 1 and 10 and the input is placed higher than 10 how do I make it send a different message to what is will be if it is between 1 and 10

Answer 1

Another way is use:
ipt = input()

if len(ipt) != 1: #whith strings, len will return hoy many character does the string have(space is also a character)
print("lol")

The thing is, the user may input something that is not even a number, so you should put all this code in try: just like this

try: # try makes that if de code inside will have an error, the program will not stop and the except code will run
ipt = int(input())
(The rest of the code)
except TypeError:
print("please input a number")

Answer 2

This is a way. You could copy and paste this in the sololearn playground.

ipt = int(input()) # input() always return a string, so you should use int() for making the input an integer

if ipt >10: # this makes that if the input is bigger than 10 the code bellow will run
print("please input a smaller number") # Be carefull whith the identation

# And here goes the rest of the code

Answer 3

AiVolt I got it working here is the code if u want to look at idk
#think of a number between 1 and 10

ipt = int(input())

if ipt >=11:
print("Cant bamboozle this code, try again")

if ipt <11:
print("You were thinking of the number",ipt)

Answer 4

You can achieve this with a simple conditional statement. Here's an example in Python:

```python
number = int(input("Enter a number between 1 and 10: "))

if number >= 1 and number <= 10:
print("The number is between 1 and 10.")
else:
print("The number is not between 1 and 10.")
```

This code prompts the user to enter a number. If the number entered is between 1 and 10 (inclusive), it prints "The number is between 1 and 10." Otherwise, it prints "The number is not between 1 and 10."