Code Solution:

Question

How does this print abc?
it = iter('abcdef') for i in range(3, 6): print(next(it), end = ")

Answer 1

𝓤𝓶𝓮𝓻 ,

here some more informtion about the mentioned code:

# this is the code correctly formatted: (i suppose this code is for *practicing purpose* or from a *challenge*, since the result could be achieved in a more simple way)

it = iter('abcdef') # (1)
for i in range(3, 6): # (2)
print(next(it), end = '') # (3)

> (1) iter() is a built-in function and creates an iterator object from the string.

> (2) range(3, 6) creates 3 loop iterations, the same could also be achieved by using:
for i in range(0, 3): or for i in range(3):

> (3) end = " uses wrong quotes, the code currently uses 1 double quote, but should be 2 double quotes or 2 single quotes
next() is retrieving the next item from the iterator, then it is printed out in the same line.

the probably shortest way to achieve the same could be:

print('abcdef'[:3])

Answer 2

There is created an iter object, which will be iterated in for loop.

This is similar to:

it = iter('abcdef')
print(next(it), end = '')
print(next(it), end = '')
print(next(it), end = '')

Answer 3

Bob_Li
I think most likely the code is from a challenge. The part of <range(3, 6)> is to make thing confusing.

Answer 4

you can just use

s1 = 'abcdef'
for i in range(3):
print(s1[i], end='')

unless it's a really big string, using iter is just overkill.

Answer 5

Use same it as it is

s1 = 'abcdef'
for i in range(3):
print(s1[i], end='')

unless it's a really big string, using iter is just overkill.