What is wrong with my code

Question

x = int(input('choose a number from 1 to 3 '))
if x ==1:
print ('1 oh cool')
else:
if x==2:
print('2 oh cool')
else:
if x==3:
print('3 oh cool')

Answer 1

You wrote the second "else" inside the condition "if x==2:"

x = int(input('choose a number from 1 to 3'))
if x ==1:
print (': 1 oh cool')
else:
if x==2:
print(': 2 oh cool')
else: #debug
if x==3:
print(': 3 oh cool')

Answer 2

nums ={1:"1 oh cool",2:"2 oh cool", 3:"3 oh cool"}
x = int(input())
if x in nums:
print(nums[x])
else:
print("wrong input")

Answer 3

also if you use python version >=3.10 then you can use match-case(switch-case in other languages):
x = int(input())
match x:
case 1:
print ("1 oh cool")
case 2:
print("2 oh cool")
case 3:
print("3 oh cool")
case _:
print("wrong input")

Answer 4

I mean thx *guys

Answer 5

Thx giys

Answer 6

Krauz The Jester, your code will not work since you capitalized the statements and did not indent

Answer 7

Pariket, it is recommended but not necessary. It just clarifies code, there is no other difference (could also be that the `elif` variant is interpreted faster). The real problem is what Vasiliy said.

Answer 8

Your code has a problem with indentation