How and what is the output is this?

Question

long i=0;
for(i;i<10;i++)
i+=5;
cout<<i;

Answer 1

#include <iostream>
using namespace std;

int main() {
//How and what is the output is this?

long i;
for(i=0;i<10;i++){
i+=5;//i=0+5=5 ,i=5+1=6(i++),i=6+5=11
//11+1(i++)=12 it will not enter the condition
cout<<i<<" ";}
return 0;
}

Answer 2

As you have initialised f=0.01 and you have not initialised 0.01 in if so it is implicitly converting it to double and answer is 0

Answer 3

Yes

Answer 4

Atul
And for this?
float f=0.01;
if(f==0.01) printf("1");
else printf("0");

Answer 5

Atul
int x=3;
while(x++<10)
x+=2;
Printf(x);

Answer 6

Atul
U mean if double f=.01 and f==0.01 would have printed 1?

Answer 7

For Loop is coded wrongly..
I should have integer data type