Can anyone explain why this code returns TypeError?

Question

def decor(func):
return "=" + func()+ "="

@decor
def sayhi():
return "sayhi"

print(sayhi())

Answer 1

As it is with y in the decor function, it will give you a NameError since the variable name y doesn't exist in that scope.
I'm going to assume you meant for y to be func() so that it would look like;

def decor(func):
return "=" + func() + "="

In which case you will get a TypeError, because 'sayhi' is of type 'str' string and is not callable. To then get the expected output of;
"=sayhi="
you would need to remove the parentheses from your attempt to call the function in the print call

print(sayhi) # change this to fix code

In case your wondering why, it's because your decorator is functioning the same as this;

def decor(func):
return "=" + func() + "="

def sayhi():
return "sayhi"

decor_func = decor(sayhi)
# decor_func is a string
print(decor_func)

Answer 2

y is not a string, but "y" is. plus, the error will tell you what line and also give you more info like what type can't be added to what

Answer 3

You did not yet fully understand decorator.
decor should return a function.

Answer 4

Slick ,Frogged ,ChaoticDawg
There was a typo error in code and it has been corrected now, pls can you still help check why it is returning TypeError. Thank you guys

Answer 5

Gmuhammed🇳🇬 (CHALLENGE ACCEPTED)
I already answered and explained, as I assumed there was this typo.

Answer 6

ChaoticDawg Thank you, I understand now.