Answer 1

if you want to iterate with i as index of the tuple list, you must iterate it over a range object...

for i in range(len(contacts)):
# contacts[i] is the (i+1)th item

by iterating over contacts, you will get each item of the list:

for t in contacts:
# t is each tuple

from the tuples, you can access each value by using square brackets notation as for lists...

for t in contacts:
# t[0] is the name (string)
# t[1] is the age (number)

or unpack the tuple while iterating...

for n, a in contacts:
# n is the name
# a is the age

then to find the tuple with 'name' and get its age:

answer = None
for n, a in contacts:
if (n == name):
answer = a
break # exit the loop as we have found name

then we can output the result:

if answer is None:
print("Not found")
else:
print(name,"is",age)

there could be make a lot of improvements, but that's another topic ;)

hope this help! :)

Answer 2

Convert the tuple to a dictionary.

Answer 3

It's much more convenient to do this...

dt = dict(contacts)

Then you can easily access the values by the key.

Answer 4

Charlie DCH --> I think you meant - why would I use a dictionary instead. It reduces the lines of code when converting the tuple to a dictionary and then you have easy access to retrieve the values by the key. Python is quite smooth in many ways.

Answer 5

Charlie DSC --> You need an if else statement like this...

if name in dt:
print(name + " is " + str(dt.get(name)))
else:
print("Not found")