i need help 😅

Question

public class Main {
public static void main(String[] args) {
int a = 100;
int b = 25;
int c = 5;
System.out.println(! (a! = b | | b <= c)); // returns false because ! (not) is used to reverse the result
}
}

Answer 1

There is not an error !
Because the logical operator "or" return the first true evaluated in a logical expression. So (a!=b ||b<=c) is evaluated to true because a!=b is true.
Next the not operator bring to false the result.
Ipang perfectly answered to your question

Answer 2

Yes, that's right. Additionally, logical OR operator only evaluated `a != b` in this case, since that evaluates to true, the right hand side operand `b <= c` is abandoned.

Logical OR operator only needs one true value, and it was found in `a != b` hence `b <= c` evaluation was unnecessary.

You may lookup on 'short circuit evaluation' online for more on that 👍

(Edit)
Careful when writing operator, I don't know whether it was because of copy/paste problem or what; but look at how `!=` and `||` was written in the snippet.

Answer 3

It may be an issue with operator precedence. Try !( (a != b) || (b <= c) )

Answer 4

Make sure it was written correctly:

System.out.println(! ( a != b || b <= c ) );

Answer 5

still doesnt work