I don't need a round-off value ,help me out...

Question

import java.util.Scanner;

public class Program
{
public static void main(String[] args) {
Scanner scanner = new Scanner(System.in);
int amount = scanner.nextInt(); /*Amountip = 1,00,000*/
int month1 = amount /10;
int balanceAm = amount-month1;
int month2 = balanceAm/10;
balanceAm = balanceAm-month2;
int month3 = balanceAm/10;
balanceAm = balanceAm-month3;
int month4 = balanceAm/10;
balanceAm = balanceAm-month4;
int month5 = balanceAm/10;
balanceAm = balanceAm-month5;
float month6 = balanceAm/10;
float x = month6 ;
int value = (Math.round(x));

int finalAm = balanceAm-value;
System.out.println(finalAm);

// find the closest int for the double

}
}
Expected out : 53144
But I got this output : 53145

Answer 1

Alphin K Sajan Ohh.. didn't notice. 😀😀

Answer 2

Pradeep kumar V

Use ceil instead of round and take amout in double. Finally cast double to int to get actual result.

One more thing don't write hard code logic even you can use loop to get final amount.

Answer 3

I Am Groot ! No prob sir , happens 😂