What is the output of this code? print('gameofdice'[ ::2])

Question

Answer is gmodc. But I didnot know how it cames. Can anyone help me to understand this

Answer 1

[start:stop:step]

- start index (here 0)
- stop index (here the end of the string)
- step = 2
'gameofdice'
^ ^ ^ ^ ^
0 2 4 6 8

Answer 2

This will print "gmodc" as mentioned by Pranav Kalro.
In the code above, you haven't given the starting and ending value. So, it will take the starting of the list and ending value as the ending value of list by default..
Moreover, you've given the step of 2 so, it will print all the strings with the 2nd element..
So, the output will be:
g-0(index,can be taken as 2nd letter) letter(will be printed)
a-1st letter
m- 2nd letter (will be printed)
e-1st letter
o-2nd letter(will be printed)
f-1st letter
d-2nd letter (will be printed)
i-1st letter
c-2nd letter (will be printed)
e-1st letter
Observe the above code carefully and analyze what's happening there.

Answer 3

The output is 'gmodc'. It is giving every alternate letter of the word 'gameofdice'.

Answer 4

This code may help you understand how string/list indexing works.

https://code.sololearn.com/c97WRsMP3F6b/?ref=app

Answer 5

Thank you so much

Answer 6

Tq all

Answer 7

[::2] skips and jumps to the 2nd element of the string "gameofdice" ... thus if you consider gameofdice as g:0 a:1 m:2 e:3 o:4 f:5 d:6 i:7 c:8 e:9 then it executes as 02468 i.e- gmodc
#hope it helps