Why is x not incremented or decremented in the first program making x equal to 1 and what also makes the second program invalid?

Question

//first program
var x = 1;
var y = 4;
function func() {
while(y > 0) {
x++;
y--;
}
}
document.write(x);

//second program
var arr = [1, 2, 3];
arr[0].push(4);
console.log(arr);

Answer 1

If you actually called the function.

var x = 1:
var y = 4;
function func() {
while (x > 0) {
x++;
y--;
}
}

func();

document.write(x)

Answer 2

First program:
The function never executes. It won't do anything to the program, since it wasn't called.

Second program:
The push is a method of the array prototype. arr[0] is 1, a number, and since I remember numbers are not arrays, and there isn't a push method for numbers, therefore it will cause an error

Answer 3

Airree So in what kind of scenario would x be 5 with the while loop still wrapped inside the func function?

Answer 4

Airree wow, thanks for your help. God bless you for me 😁👍

Answer 5

Airree, I understand your explanation for the second program but for the first, are you saying that the function will only execute when we have "do {}" in the program?

Answer 6

No, that's not what I'm saying. The while loop, as you can see, is wrapped inside the func function. You might have heard, but functions are only executed, when they are called. The func function is never called, therefore the while loop doesn't execute. If it wouldn't be inside a function, yes, x would be 5

Answer 7

The function in the first program will only execute if you add func() to your program. You’ve defined it but not called it. Also, unless x and y are global variables, the function won’t recognize them. You can fix this easily by changing the function to accept two values func(x,y), and then pass these two values when you call the function.