I need someone blessed to please explain why the result of this code is 30

Question

var x=0;
for(var i=0; i<10; i++) {
for(var j=0; j<=2; j++) {
++x;
}
}
alert(x);

Answer 1

the first for loop runs exactly 10 times because the sign is "i<10"

the second runs 3 times because the sign is "i<=2" which is like saying "i<3"

since the loop that runs 3 times is inside the 10 times loop, it runs the 3 loop 10 times. basically the 3loop*10loop or 3*10 = 30

so x = 30

Answer 2

i:0, 1, 2, 3, 4, 5, 6, 7, 8, 9
Then i does not become less than 10.
j:0, 1, 2
Then j does not become less than or equal to 2.

10*3=30

Edit: The above numbers listed are the values i and j could possibly take.

Answer 3

I am not exactly sure how to find a blessed person.

Answer 4

Prometheus 🇸🇬 I'm afraid to say that I still don't understand

Answer 5

Yeah, 10 times ( from 0 to 9) x 3 (0, 1 and 2)=30.
If you put j<2 then the result is 20.

Answer 6

Hi Mofey. The answer is simply: in nested for(m.. (for(n..)), the result is the multiplication of m * n, in this case i=0 i<10 => i takes values 0 till 9, total 10
case j=0 j<=2 => j takes values 0, 1 & 2, therefore 3=> i=10 * j=3 => x = 30

Answer 7

inner loop runs three time (j<=2 0,1,2) for each main loop which is 10 times (i<10)
when mainloop run first loop inner loop will run three time and it goes on until i <10
0 to 9 is 0123456789 which is 10 times.

Answer 8

I want to know where is the output statement? Like system.out.println....

Answer 9

whats the error message?

Answer 10

Using the formula for series as the loop from 0-9 this is 10 numbers for 0-1, sum of the first number is 15 and this is repeated twice, so that's why the sum is 30. (Sum (0-9)) *2 = (5*(6/2))*2= 15*2 = 30 🤗🤩

Answer 11

i would suggest not to apply equation to solve if you beginner go with logic you will get clear and later on you can apply any equation you want.

Answer 12

Mofey It's a nested for loop. It runs the second for loop 10 times, which runs twice. 10 * 3 = 30

Answer 13

The loop for (var j = 0; j <= 2; j++) {
++x
}
gives x = x + 3 each time.
The i loop runs 10 time.
so each time x = x + 3
so 30

Answer 14

List of i to be looped: (1,2,3,4,5,6,7,8,9, 10)
List of j to be looped:
(1,2, 3)
NB: the values of i and j are incremented before their conditions are checked

For each value of i, the second for-loop evaluates 3 times(so x increases by 1 each time and will have a final value of 3) .
The first for-loop of i will be evaluated 10 times in all.

Since alert(x) is out of the loop it will return the cumulated value of x which will be 30.

So when {i =1, x=3}, {i=2, x=6},{i=3, x=9}, {i=4, x=12}, {i=5, x=15}, {i=6, x=18}...

Answer 15

Loop increment... playing around with inner loop and creating a 3 times of the outer loop. ...great though ...thumbs up

Answer 16

Because you have <= sign befor 2 in the line with second FOR