Please Help!!!I need answer with C or C++

Question

(n!*m!)/!(m+n)
n!=1
n=0
n!=1*2*3*....*(n-1)* for n>0

Answer 1

#include <iostream>
using namespace std;
long long fact(int n){
int i = n;
long long fact = 1L;
if(i != 0){
while(i > 0){
fact *= i;
i--;
}
}
return fact;
}
void compute (int n, int m){
double ans = (fact(n) * fact(m)) / fact(n+m);
printf("%f",ans);
}
int main() {
int n = 5;
int m = 10;
compute(n, m);
return 0;
}

the code for your given problem is as above but are you sure this formula (n!*m!)/!(m+n) is correct?

Answer 2

Υες