Can anyone explain me this python code

Question

x = True

y = False

z = False

if x or y and z:

    print("yes")

else:

    print("no")

Answer 1

Interesting. So what's happening is that the expression is being evaluated as x or (y and z) == True.

If you want it to get evaluated to False, you should specify the order of precedence as (x or y) and z.

Answer 2

The "or" operation evaluates to True if either operands are True.

True or False == True

The "and" operation evaluates to True only if both operands are True.

True and False == False

Therefore, x or y and z evaluates to False, which makes the else statement be executed.

Answer 3

It's good practice to use parenthesis to define the order of your logical operations.
Furthermore, if you are not sure of what to expect with a complex logical expression, try to imagine the different cases given the inputs or even write it down and go as far as making a truth table if needed.
Some things become intuitive only after a while.

EDIT : if you're interested in operator precedence in python, you can find it here :

https://docs.python.org/3/reference/expressions.html#operator-precedence

Answer 4

https://code.sololearn.com/c3GXx2RL4QWY/?ref=app

Answer 5

but the output is yes .

Answer 6

AND is higher precedence than OR in python and is evaluated first