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what have i to do, if i want that the program always writes for example :
0+1
1+2
3+3
6+4
10+5
15+6
...
because now it just writes
1
3
6
10
15
...
and maybe if it works, can i make then
0+1=1
1+2=3
3+3=6
6+4=10
#include <iostream>
using namespace std;
int main(){
int i;
int sum = 0;
for (i = 1; i <= 100; i++){
sum = sum+i;
cout<<sum<<endl;
}
cout<<sum;
return 0;
}
1 Stimme
5 Antworten
what is that output of this program
#include<iostream.h>
using namespace std;
int main()
{
int e1=5, e2=20, e3 = 15;
int *arr[ 3]= {&e1, &e2, &e3};
court<<*arr[*arr[1]-19];
return 0;
}
0 Stimmen
3 Antworten
Fill in the blanks that define an abstract Animal class and a dog class that inherits from it.
class Animal{
public:
virtual void bark()=___;
};
class Dog __ Animal{
public:
_____bark(){
cout<<"Woof!";
}
};
1 Stimme
2 Antworten
What is the output of this code? int result = 0; for (int i = 0; i < 5; i++) { if (i == 3) { result += 10; } else {
1 Stimme
3 Antworten
What is wrong with this code?
-
-
<!Doctype html>
<head>
</head>
<body>
<form>
<input type="text" id="input">
</form>
<button type="button" id="button">Click here</button>
<script>
var input=document.getElementById("input");
var button=document.getElementById("button");
function display() {
if (button.clicked == true) {
console.log("input");
}
};
display();
</script>
</body>
0 Stimmen
7 Antworten
hello. please help me to understand this code:
int main(){
int i=50, b=20,c=30;
i=c,b;
cout<<i<<endl;
i=(c,b);
cout<<i<<endl;
}
outputs:
30
20
I don't realize, what does the parantheses change (3 and 5 line)
1 Stimme
3 Antworten
#include <iostream>
using namespace std;
class A{
public:
void f1();
};
class B : public A{
public:
virtual void f1();
}
int main()
{
A * obj = new B;
obj.f1();
}
Ques: can we write virtual before an overridden function from the base class?? if yes which f1() should it call base class f1() or derived class f1()???
0 Stimmen
1 Antwort
why this program show compile error?
#include<iostream>
using namespace std;
class a{
public:
int f(){cout<<3;}
int f(int a){cout<<a;}
};
class b:public a
{
public:
int f(){cout<<5;}
};
int main()
{
b obj;
obj.f(7);
}
0 Stimmen
4 Antworten
What is the output and how dose it came ?
#include <iostream>
int main() {
std::cout << (10 & 6) << std::endl;
std::cout << (10 | 6) << std::endl;
return 0;
}
0 Stimmen
3 Antworten
double arr[]={5,2,7,8,11,9};
int n = sizeof(arr) / sizeof(arr[0]);
double sum = 0;
for(int i=0;i<n;i++)
{
sum+= arr[i];
}
double avg = sum / n;
cout<< "avarage ="<< avg<< endl;
return 0;
)
/*what does int n= sizeof(arr[]) /sizeof(arr[0]);
do, can someone explain that line for me*/
0 Stimmen
3 Antworten
What is the output of this code? int result = 0; for (int i = 0; i < 5; i++) { if (i == 3) { result += 10; } else {
-5 Stimmen
6 Antworten
Thanks to the lack of parenthesis and curly braces, the code is always much clearer and more readable than C or C++ code!
Example: C++ vs Python
if (x>0)
{ std::cout << "x is positive."
<< std::endl; }
if x>0:
print("x is positive.")
#Python4president
1 Stimme
6 Antworten
Int x=0;
For (int i=0; i <8; i++) {
x=i*i;
} what will be the output ; and what will be the value of( i) after the for loop
-1 Stimme
2 Antworten
pairs = {1: "apple",
"orange": [2, 3, 4],
True: False,
None: "True",
}
print(pairs.get("orange"))
print(pairs.get(1))
print(pairs.get(12345, "not in dictionary"))
the output is
［2, 3, 4］
False
not in dictionary
why is print(pairs.get(13345,"not in dictionary")) giving the output not in dictionary.pls I nid explanation
2 Stimmen
4 Antwortenis there a way I can store all the values of x in this short code without having to display them using cout?
int main() {
for (int x=0; x<5; x++){
//how do i store the all the values of x without having to display them?//
}
3 Stimmen
5 Antworten
WY I get a rundum number from memory when I run this code
#include <iostream>
using namespace std;
int main ()
{
int array [5];
for (int x = 0; x < 5; x++) {
array [x] = 42;
cout << x << ': ' << array [x] << endl;
}
return 0;
}
if I replace ': ' with ": " every thing works well.
0 Stimmen
2 Antwortenhi, me newbie, started last day, right now I wrote a code using "do", the out is 2,4,6, while condition is <5. why or how output is exceeding 5. thanx in advance
int a=2;
do {
cout<<a <<endl;
a+=2;
}
while (a <5);
0 Stimmen
5 Antworten
Fill in the blanks to make the image circled and blurred with 30% sepia applied.
-2 Stimmen
2 Antworten
why not this program output 7 and why it shows compiler error ???
#include<iostream>
using namespace std;
class a{
public:
int f(){cout<<3;}
int f(int a){cout<<a;}
};
class b:public a
{
public:
int f(){cout<<5;}
};
int main()
{
b obj;
obj.f(7);
}
1 Stimme
3 AntwortenCan someone help me please. I can understand the result of the cout << p << endl;
#include <iostream>
using namespace std;
int main() {
int x = 8;
int *p;
p = &x;
cout << *p << endl;
cout << p << endl;
cout << &p;
return 0;
}
1 Stimme
6 Antworten
which of the following statements are correct for accessing x?and why?
#include <iostream>
using namespace std;
class test{
public:
int x=9;
};
int main()
{
test t;
test *p=&t;
}
select all that apply:-
a) t.x
b) p.x
c) t->x
d) p->x
1 Stimme
3 Antwortenwhy this output only comes 3 and why not output 123?
#include<iostream>
using namespace std;
class A{
public:
virtual void f(){cout<<1;}
};
class B:public A{
public:
void f(){cout<<2;}
};
class C:public B{
public:
void f(){cout<<3;}
};
int main()
{
B *p=new C;
p->f();
}
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3 Antwortenif i download the programs for c++ on my pc ( codebuilds and the compiler ) and i want to write a program in my package ( workspace ) i create a new file and write smthing beginning
#include <iostream>
using namespace std;
int main ()
{
...
}
and i want to run it, it always runs this first program : Hello World. and not my written program how can i run just my written program ?
have i maybe to write anything else as
int main () {} ?
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16 AntwortenI have an iphone 5s and when I test the code, I see no difference from thick and 700. I also wrote:
CSS:
.p thickest {
Font-size: 900;
}
Html:
<p .thickest>This should be "BOLDEST"
</p>
And the last 3 were the same size. Could it be the phone or is the code wrong?
0 Stimmen
5 Antworten
hey guys, I've been trying to work out the formula 'v=I*r'. But whenever I run the program and input values for I and r, it doesn't give the right answer.
This is the code
#include <iostream>
using namespace std;
int main() {
int i,r;
int v = i*r;
cout<<"what is the value of i?\n";
cin>>i;
cout<<"what is the value of r?\n";
cin>>r;
cout<<"voltage ="<<v<<endl;
return 0;
}
p/s: I'm new to programming
1 Stimme
8 Antwortenvery important: as i can do so that the user can enter data into a .txt file .
i try with:
...
float Data;
fstream Leer(temp.txt , iOS::app);
if(Leer.good())
{cout<<"Enter data: ";
cin>>Data;
Leer>>Data;
Leer.close();
}
other way?
Help please.
0 Stimmen
2 Antworten
can someone help solve this:what is the output of this;
class A {
public:
A () { cout << "a";}
~A () { cout << "b" ;}
};
class B
public:
B () { cout << "c" ;}
~B () {cout << "d" }
};
int main () {
B b
A a
};
1 Stimme
3 Antworten
java learning
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1 Antwort
Wher is mistake?
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5 Antworten
Java programming loop statements
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2 Antworten
Hi, I need assistance aka HELP!
I've done this calculation in various ways some of printed nothing but zeros non stop.
Using while loop calculate all numbers 1 to 1000 add numbers to sum = sum + i
int sum = 0;
// use a while loop to calculate the sum of 1 to 1000
While(int sum = 0; sum >= 1000; sum = sum + I){
System.out.println(sum);
}
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4 Antworten
java class Addquot;">"quot;
quot;;">"quot;;"awesome");"dolor""haha""hihi""hoho""huhu");"ipsum""is""sit"{}+=addadd("hehe"add("lorem"add("this"classconstructor(...words)newprint()returnthis.words 1 Stimme
4 Antworten
Why not working
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4 Antworten