Fill in the blanks to create a pattern that matches strings that contain 3 characters, out of which the last character is an exc

the answer is r

answer is r"..!$"

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You need to match two "any character", followed by an exclamation mark. In regular expressions, "any character" is matched by using a dot. And the exclamation mark is a regular character, so you match it using... an exclamation mark :) So you are looking for: ..!

str = r "I am \r\a\w!"

ill in the blanks to create a pattern that matches strings that contain 3 characters, out of which the last character is an exclamation mark. answer is r"..!$"

ans is r

r use

Sounds difficult and is difficult, sorry

use +

Helpful

Fill in the blanks to match strings that are not entirely composed of digits. import re pattern = r"[ ^ 0-9 ] " m = re.search(pattern, "Hi there!")

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r"(42)+$"

It's answer is r"..!$"

answer r"..!$"

Fill in the blanks to match strings that are not entirely composed od digits

Is this answer correct? I fill ! in the blanks but it show false.

str = r "I am \r\a\w!"

.. !