Can I do a concatenation of 2 chars?

Question

Like this: 'a'+'b'="ab"

Answer 1

you can with strings

don't forget to add
#include <string>

string x;
x="a";
x+="b";

and treat all chars as strings (use double quote marks "a")

notice the following
cout << "a" + "b";
results in error
whilst

string x = "a";
cout << x + "b" + "c";
is valid
the reason for that is since you can concatanate into a string (second case) but cannot concatanate const characters (first case)

whom ever wish to elaborate on this please do

Answer 2

Just to add to the previous answer, if you have already declared char's and aren't adding string literals like Burey said (string literals are the quotes, like "a"), you can use a string library function:

char a = 'a';
char b = 'b';
string str = ""; //declared empty string

str.append(1, a);
str.append(1, b);
cout << str << endl; //outputs "ab"

When you use append with a character, the first number you pass into the function is the number of copies of the character you want to append onto the string. For example, str.append(4, a) would result in str = "aaaa"; You can also use it with character literals as well:

str.append(2, 'g'); // str = "gg";

Answer 3

Great, thanks! So that's why when I do something like this:

char a='3';
cout << a-'0';

The output will be an int (it will subtract the ASCII codes of chars 3 and 0)?