How do i creat the .len function in code

Question

This seems right but it keeps giving me errors not sure what im doing wrong
x=[6,8,9,10,8]
num=0
y=(num+1)
while num>=0
if x[y] not >=0 or not <=0
print(y)
break
else:
num+=1

Answer 1

What output do you expect? And what is your if-statement supposed to test?

A number is always >= 0 or <= 0.

Answer 2

# Hi, Brayden Stevens !
# Maybe you can try something like this:

def my_len(lst):
i = 0
while True:
try:
lst[i]
except IndexError:
return i
else:
i += 1

x = [6, 8, 9, 10, 8]
print(my_len(x))

Answer 3

# Hi, Brayden Stevens !
# It's more easy to write:
...
if not x[y] >= 0 or not x[y] <= 0:
print(y)
...

# as the following:
...
if x[y]:
print(y)
...

Answer 4

1. num starts as 0 and only gets incremented, so is always >= 0. What exactly did you intend with "while num >= 0"?
2. What is "y" for?
3. Double check the indentation of the "else" part.

IMHO, the code is way overcomplicated for this task. A clean approach is to just iterate on the items and increment a counter.

Another hint: use meaningful variable names. It helps a lot in debugging and improving your code.