[SOLVED] What's wrong with my code? program created to solve many sets of quadratic equations

Question

#include <iostream>
#include <cmath>
using namespace std;
int a, b, c, d;
double x1, x2;
int main()
{
cout << "Input for a: ";
cin >> a;
cout <<"Input for b: ";
cin >> b;
cout << "Input for c: ";
cin >> c;
cout << "\n";
if (a = 0){
cout <<"Not Quadratic\n";
if (b = 0){
cout << "a = 0\nb = 0\nBye";
}
else{
x1 = (-c/b);
cout << "x1 = "<< x1;
}
}
else{
d = (b^2-(4*a*c));
if(d<0){
cout << "No Real Answer. Fail to take the square root of Negative Value.\n";
}
else{
x1 = (-b+sqrt(d))/(2*a);
x2 = (-b-sqrt(d))/(2*a);
cout << "Root 1: x1 = "<<x1<<endl;
cout << "Root 2: x2 = "<<x2<<endl;
}
}
return 0;
}

Answer 1

The "^" is a bitwise XOR operator, not exponent.
Use "pow ()" function from cmath to find the power of the number instead.

Answer 2

I found 3 bugs.
#include <iostream>
#include <cmath>
using namespace std;
int a, b, c, d;
double x1, x2;
int main()
{
cout << "Input for a: ";
cin >> a;
cout <<"Input for b: ";
cin >> b;
cout << "Input for c: ";
cin >> c;
cout << "\n";
if (a == 0){ //Debug 1
cout <<"Not Quadratic\n";
if (b == 0){ //debug 2
cout << "a = 0\nb = 0\nBye";
}
else{
x1 = (-c/b);
cout << "x1 = "<< x1;
}
}
else{
d = (b*b-(4*a*c)); //debug 3
if(d<0){
cout << "No Real Answer. Fail to take the square root of Negative Value.\n";
}
else{
x1 = (-b+sqrt(d))/(2*a);
x2 = (-b-sqrt(d))/(2*a);
cout << "Root 1: x1 = "<<x1<<endl;
cout << "Root 2: x2 = "<<x2<<endl;
}
}
return 0;
}

Answer 3

Thank You Everyone!