Answer 1

Because findall like i believe any other counting method can't be overlaping. Try this:

import re
a = re.compile(r"mama")
print(a.findall("mamamama"))

you could count it

1. "ma ma" ma ma
2. ma "ma ma" ma
3. ma ma "ma ma"

but you only got 1 and 3 cuz 2 is part of both 1 and 3.

you will get the same result with:

text = "mamamama"
i = text.count("mama")
print(i)
--> 2