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# Store is closed

hour = int(input()) day = int(input()) # your code goes here if day==1 or day==2 or day==3 or day==4 or day==5 and 10<=hour<=21: print("Open") else: print("Closed") if day==“1” or day==“2” or day==“3” or day==“4” or day==“5” and 10<=hour<=21: print("Open") else: print("Closed") When I write the first program the answer for 23 and day=2 will be open that is incorrect ! But when I write the second one with “” the answer for 23 and 2 will be correct but not for others!!can anyone help me plz?

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Hi Mahdieh! It's always better to separate logical operators using parenthesis. The reason is that is operator precedence. Here, and operator has higher precedence than or operator and rational operators( < > ==). So, it needs to be like this if(day == 1 or...) and (10 <= hour <= 21) But, you can think about other easy ways to solve this challenge like using range() and so on.

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Python Learner Dear Python learner I tried your answer and It worked.thanks.

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Maybe you can use range() to check the day of week and hour of day. No guarantee though, hidden cases are part of the challenge. if day in range( 1, 6 ) and hour in range( 10, 22 ): # Open else: # Closed P.S. Comparing either <day> (int) with string literals isn't what we're supposed to do. Except where we read <day> as string also - we don't use int() to convert input string into int.

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Ipang yes I saw other ways and tried them too but it was weired why this way doesn’t answer.thank you for your help

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check it if you need hour = int(input('Enter the Hour: ')) day = int(input('Enter the Day: ')) h = [x for x in range(10, 22)] d = [x for x in range(1, 8)] if (hour in h) and (day in d): print('Open') else: print('Closed')

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Krishnam Raju M thank you Krishnam