Help me with this exercise

Question

##ACTIVITY: Dictionary You are working on data that represents the economic freedom rank by country.Each country name and rank are You are working on data that represents the economic freedom rank by country.Each country name and rank are stored in a dictionary, with the key being the country name.Complete the program to take the country name as input and output its corresponding economic freedom rank.In case the provided country name is not present in the data, output "Not found".stored in a dictionary, with the key being the country name.Complete the program to take the country name as input and output its corresponding economic freedom rank.In case the provided country name is not present in the data, output "Not found".

data = {
'Singapore': 1,
'Ireland': 6,
'United Kingdom': 7,
'Germany': 27,
'Armenia': 34,
'United States': 17,
'Canada': 9,
'Italy': 74
}

a =input()

for x in data:

if x == a:
print (data[x])

#else:
#print('Not found!')

Answer 1

In the problem description, it says to print "Not found" if the input isn't recognised, but your output says "Not Found!". Could this be the reason the solutions above are not working?

Answer 2

#try this, simple and short
data = {
'Singapore': 1,
'Ireland': 6,
'United Kingdom': 7,
'Germany': 27,
'Armenia': 34,
'United States': 17,
'Canada': 9,
'Italy': 74
}
key = input()
print(data.get(key, "Not found"))

Answer 3

do it in one line .

print(data.get("user input","Not Found ! "))

Answer 4

Can also be done using else clause with for loop.

data = {
'Singapore': 1,
'Ireland': 6,
'United Kingdom': 7,
'Germany': 27,
'Armenia': 34,
'United States': 17,
'Canada': 9,
'Italy': 74
}

a =input()

for x in data:
if x == a:
print (data[x])
break
else:
print('Not found!')

Answer 5

data = {
'Singapore': 1,
'Ireland': 6,
'United Kingdom': 7,
'Germany': 27,
'Armenia': 34,
'United States': 17,
'Canada': 9,
'Italy': 74
}

country = input()

if country in data:
print(data.get(country))
else:
print(data.get(country, 'Not found'))

# or in one line print(data.get(country, "Not found"))

Answer 6

# Another way you can use it

data = {
'Singapore': 1,
'Ireland': 6,
'United Kingdom': 7,
'Germany': 27,
'Armenia': 34,
'United States': 17,
'Canada': 9,
'Italy': 74
}

country = input()
print("Not found" if country not in data else data[country])

Answer 7

Like this it gives a number when the country is found, and "Not found", once, if the country is not found:

data = {
'Singapore': 1,
'Ireland': 6,
'United Kingdom': 7,
'Germany': 27,
'Armenia': 34,
'United States': 17,
'Canada': 9,
'Italy': 74
}

a =input()

y = 0

for x in data:

if x == a:
print (data[x])
y = 1

if y == 0:
print('Not found!')

Answer 8

This is the right answer:

data = {
'Singapore': 1,
'Ireland': 6,
'United Kingdom': 7,
'Germany': 27,
'Armenia': 34,
'United States': 17,
'Canada': 9,
'Italy': 74
}
country = input()

if country in data:
print(data.get(country))

else:
print(data.get(country, "Not found"))

Answer 9

I dont no why this no pass in the exercise. The Else no stop in output. This work in infinite loop.

Answer 10

"#else" is comment, not is code executable.:
#else is comment
else: #is Instruction.
#And you have to use "break" to stop the loop.
if x==a:
print(data[a]);#or data[x];
brea;

Answer 11

Universal I forgot this python feature.:)
Michael Interesting.

Answer 12

No. The problem Its Not my # in else. I put because I test the program. But the solutions in here doesnt work. Thanks.

Answer 13

I don't understand. I better retire and leave you in the hands of the Solo Learn community

Answer 14

for key, value in data.items():
if a == key:
print(f'The country {key} has the economic rank value of {value}')

#update: adding incorrect input handle

data = {
'Singapore': 1,
'Ireland': 6,
'United Kingdom': 7,
'Germany': 27,
'Armenia': 34,
'United States': 17,
'Canada': 9,
'Italy': 74
}

a =input()

for key, value in data.items(): # dict.items() returns key, value pairs. Iteration is done over key, value, if key == a than print its value

if a == key:
print(f'The country {key} has the economic rank value of {value}.')

print('Not found!') # if a does not meet any dict key than print "Not found!"

code is working as expected, you need more help? Do you wanna implement it as function?

Answer 15

The exercise is Pratice National Currency on Dictionary Fuctions, of course Intermediate Python. Nothing, doesnt work.

Answer 16

Wilbur Jaywright You can always delete a comment you've made if you think it is no longer relevant.

I'm curious though about why you would "report" a comment you've made. Unless it was spam or offensive, why would you report it?

Answer 17

Wilbur Jaywright It's good that you would now consider it necessary to offer an explanation with a code snippet, but I wouldn't consider not doing so a reportable offence, personally. I don't think that goes against the guidelines. I could be wrong though.

I think, it you see something like this, a downvote would be more appropriate (which it appears someone did to your comment).

Answer 18

Wilbur Jaywright Ah, well I haven't seen that message, so I'm not sure. You can delete your comment even if someone has upvoted it. But it's up to you of course.

Answer 19

Allan QBit I had forgotted about the dictionary get method. That will be really useful! :-)

Answer 20

data = {
'Singapore': 1,
'Ireland': 6,
'United Kingdom': 7,
'Germany': 27,
'Armenia': 34,
'United States': 17,
'Canada': 9,
'Italy': 74
}
name = input()
print(data.get(name, 'Not found'))