 Test case 4 don't work | Sololearn: Learn to code for FREE!

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# Test case 4 don't work

Can't get the test 4 working?? https://www.sololearn.com/coach/127?ref=app money = int(input()) price = int(input()) all = price * 10 x = money - all if all <= 100: print(x) if Statements +10 XP Let's imagine you want to buy an ice-cream for 10 of your friends. Write a program that will take the money you have and the price of one ice-cream, and will output the remaining money only if you can buy that ice-cream for your all 10 friends. Sample Input 80 7 Sample Output 10 Explanation 7*10 = 70. 10 is remaining money (80-70).

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Kierren Haggerty , please place the whole description of the task, because it is visible only by Pro users, so somebody can help you.

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#This will work money = int(input()) price = int(input()) #your code goes here all = price * 10 bal = money - all if all > money : print() elif all <= 100: print (bal) elif price >= 0: print(bal)

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if Statements +10 XP Let's imagine you want to buy an ice-cream for 10 of your friends. Write a program that will take the money you have and the price of one ice-cream, and will output the remaining money only if you can buy that ice-cream for your all 10 friends. Sample Input 80 7 Sample Output 10 Explanation 7*10 = 70. 10 is remaining money (80-70).

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Just check your if condition again.. It is in reverse...

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money = int(input()) price = int(input()) total = price*10 if total<=money: print(money-total)

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money = int(input()) price = int(input()) total=price*10 #your code goes here remainder=money-total if (total>money): print() else: print(remainder) Despite all my attempt, I failed in test 4. Don't know how to resolve?

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Kierren Haggerty , I think it should be if x >= 0: ....

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this will definitely work money = int(input()) price = int(input()) total = price*10 left = money - total if (total > money): print() else : print(left) my all test cases passed

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you need to do the print() to return nothing. if you simply skip if its bigger than 100, it’ll pass that test but fail test4

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I think this is the shortest solution, money = int(input()) price = int(input()) total = price*10 if money >= total: print(money % total)

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Money= int(input()) Price=int(input()) Total= price*10 remaining_money= money - total If total <= money : Print ( x)

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a = money = int(input()) b = price = int(input()) c = total_price = b * 10 d = balance = a - c e = a//b if c <= 100: print(d) elif e >= 10: print(balance) else: print() it will defenently work try it once

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money = int(input()) price = int(input()) total=0 total = price*10 total=money-total if total >= price: print(total) elif total>=0: print(total) else: print()

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money = int(input()) price = int(input()) total = price*10 if money / price >= 10: print(money % total)

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It's not that complicated but the problem was not properly explained. The program is meant to print the difference of the money you have vs the cost of the ice-cream IF you can afford the ice cream. e.g. if money >= total: print(money - total)

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“”” this worked for me “”” a = money = int(input()) b = price = int(input()) c = total_price = b * 10 d = balance = a - c e = a//b if c <= 100: print(d) elif e >= 10: print(balance) else: print()

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Bunty and Biscuits Problem Statement: Bunty the dog wants to buy Biscuits from the Parle canteen and Britannia canteen. Buying X biscuits from Parle canteen will cost him A"(X"X) rupees and Buying X biscuits from Britannia will cost him B"(X"X) rupees. Please help Bunty to buy exactly N biscuits and minimize the money he pays