I am having error in my Calculator, and I'm not getting output

Question

import tkinter
window=tkinter.Tk()
window.title('Calculator')
window.geometry("500x600")
l1=tkinter.Label(window, text="Calculator", font=("Arial", 10), bg='red', fg='white')

l2=tkinter.Label(window, text="Input what you want to calculate here", font=('Arial', 6), bg='blue', fg='white').grid(row=2, column=2)

def cal():
x=en1.get()
print(x)

en1=tkinter.Entry(window, justify="center", width=10).grid(row=3, column=2)

y=tkinter.IntVar()
y.set()
l3=tkinter.Label(window, textvariable=y, text=" ").grid(row=4, column=2)

b1=tkinter.Button(window, text="Calculate", bg="blue", fg="white", command=cal).grid(row=5, column=2)

window.mainloop()

Answer 1

its just an typing error just retype the program with no disturbance

Answer 2

To Bi, it’s not a typing error as mentioned. The issue you have is a missing argument:

y.set() # should be: —-> y.set('test’)

needs an argument, what the associated object expected. It has to be a string.
After this the code will run.

Answer 3

Okay, will do that.
Thanks

Answer 4

Thanks, I tried that buh it give me error "object has no attribute" here is the new code.

import tkinter
window=tkinter.Tk()
window.title('Calculator')
window.geometry("500x600")
l1=tkinter.Label(window, text="Calculator", font=("Arial", 10), bg='red', fg='white')

l2=tkinter.Label(window, text="Input what you want to calculate here", font=('Arial', 6), bg='blue', fg='white').pack()

x=tkinter.IntVar()
x.set("2+2")
en1=tkinter.Entry(window, textvariable=x, justify="center", width=10).pack()

y=tkinter.IntVar()
y.set('test')
l3=tkinter.Label(window, textvariable=y, text=" ").pack()

def cal():
l3.configure(text=eval(x.get))

b1=tkinter.Button(window, text="Calculate", bg="blue", fg="white", command=cal).pack()

window.mainloop()