Skee Ball problem

Question

#include <stdio.h>

int main() {
int p;
int t;
scanf("%d%d", &p, &t);
t=(p/12);
if(t>=40){
printf("Buy it!");
}else{
printf("Try again");
}

return 0;
}
This is my attempt to solve the skee ball problem.All test case ok without one test case.Need your suggestions.

Answer 1

Try this:

#include <stdio.h>

int main() {
int score;
int price;
int result;

scanf("%d%d", &score, &price);
result =(score/12);

if(result >= price){
printf("Buy it!");
}else {
printf("Try again");
}

return 0;
}

Answer 2

points is first input
cost is second input
tickets = points / 12
if tickets >= cost
Buy it!
else
Try again

you're taking t as an input for the cost and then setting it to the tickets and comparing all ticket calculations to a cost of 40 which you don't know

Answer 3

My Python code :
points= int(input())
cost = int(input())
tickets = points / 12
if tickets >= cost:
print("Buy it!")
else:
print("Try again")