unary operators : If float x; then x=sizeof(double) then why out is 0 | SoloLearn: Learn to code for FREE!

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unary operators : If float x; then x=sizeof(double) then why out is 0

3/29/2020 3:33:58 PM

Ankit Patil

5 Answers

New Answer

+1

Because you use wrong format specifier. %d is used for `int` data. But you are actually printing `float` data. Use %f instead of %d, and it will work 👍

+2

Thanks you for helping me 👍👍👍

+1

No problem buddy 👌 And for further introduction on format specifiers, you can check these out 👇 http://www.cplusplus.com/reference/cstdio/scanf/ http://www.cplusplus.com/reference/cstdio/printf/

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Why out is 0? I don't know. In your code you don't seem to be printing anything out. But assuming you did print the <x> value, how did you do it?

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#include<stdio.h> Main() { float x; Clrscr(); X=sizeof (double); Printf(''%d",x); getch(); } This is the program Why output is 0 when float contain 4 byte and double contain 8 byte