Error in c++ function code

Question

bool validclass (char)
{
bool valid=true ;
if (char =='F' ||char = 'B'||char ='E' ){
valid = true ;
}
else if
{
valid = false ;
}
return valid ;
}

The error message was
Expected primary expression before ‘char’
Expected ‘)’ before char
Expected ‘(‘ before ‘{‘token

Answer 1

Avoid using type name for variable or function name, you risk confusing yourself over time.

******************************
bool validclass (char)

'char' is a type name. You should specify a parameter name following the type name; as follows:

bool validclass(char c)

******************************
if(char =='F' ||char = 'B'||char ='E')

Here you use '=' to compare against 'B' and 'E' while you should do as you did to compare against 'F'

if(c == 'F' || c == 'B'|| c == 'E')

******************************
else if

Your `else if` statement here is invalid; because there is no condition to evaluate and conclude whether the condition satisfies. I believe you meant to use `else` instead.

I Suggest you to review the lesson to get better understanding 👍

Answer 2

You're welcome : )

Answer 3

thank you so much !!!

Answer 4

Also you could shorten your code to:

return (c == 'F' || c == 'B' || c == 'E')

No need for setting another variable and use of ifs :)