How do I use an if statement for a string?

Question

Bit hard to explain, but what I'm trying to do is to find how many times a certain letter(s) is in a specific string. For example:

String ex = "Hello"

if ('a', 'e', 'i', 'o', 'u') are in (ex)
{
int counter++;
}

Answer 1

You can use a for loop and the charAt() method.
This method returns the char at a specific index.

String ex = "hello";
int counter = 0;

for(int i = 0; i < ex.length(); i++){

if(ex.charAt(i) == 'a' || ex.charAt(i) == 'e' || ex.charAt(i) == 'i' || ex.charAt(i) == 'o' || ex.charAt(i) == 'u'){

counter++;

}

}

Answer 2

Here is my old code

I think this code help you
https://code.sololearn.com/cUuG8snpvKF4/?ref=app

Answer 3

A recursive approach

https://code.sololearn.com/c0Axla7us3CI/?ref=app

Answer 4

Are you trying to count every matching character and increment the counter or do you want to check no. Of a and show the count, no. Of e and show the count and so on.

Answer 5

int counter = 0;
char[] vowels = {'a', 'e', 'i', 'o', 'u'};
String ex = "Hello";

for(char a: vowels)
for(char b: ex.toCharArray())
if (a == b)
counter++;
System.out.print(counter);

// or

for(char a: vowels) {
for(char b: ex.toCharArray())
if (a == b)
counter++;
System.out.println(a + " " + counter);
counter = 0;
}