 Float and double in c++ | SoloLearn: Learn to code for FREE!

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# Float and double in c++

What's wrong with this program? I know that float accommodates 7 digits and double 15 to 16 digits but why this program show result with 5 digits as the default. #include <iostream> using namespace std; int main() { float a; a=10/3; cout<<a; return 0; } The result is 3 with no digits.

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Because 10 and 3 are integers and their division results in 3. Change it to a= (float) 10/3; You have to type cast it to float.

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Sololearn probably has limitation on number of decimal points.

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Float has only 4 digit precision and the 5th digit is rounded off here on sololearn playground.

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Why don't you try it on a system or a laptop

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The reason is the order of operation of the program 1. divide the two integers (10/3=3) 2. Cast the result to float (=3.0) 3. Store the result in a As said before, there are to solutions One is to cast one of the number or both to float a=(float) 10 /3; The operations are 1. Cast 10 to float (10.0) 2. Cast 3 to float, needed to make the division (3.0) 3. Divide 10.0/3.0 (=3.33333...) 4. Store the result to a Or better put directly float numbers a=10.0/3.0; Which does: 1. Divide 10.0/3.0 (=3.3333) 2. Store the result into a

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I used cxxdriod Is it different on laptop?

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Thanks Kit Delano Cat When we use fixed or setprecision, does mentioning float or double matter, I mean what if we don't write float or double?

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Thank you so much Kit Delano Cat, I just learnt something new today.

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I tried 10.0/3 and it showed with only 5 digits not seven

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I read that float has 7 digits l even tried this one #include <iostream> using namespace std; int main() { double a; a=10.0/3; cout<<a; return 0; } the result was 3.33333 (only 5 digits)

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How can I have more digits ?

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I used it but as I said it only showed 5 digits

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Because here 10 and 3 both are integers so in c++ output of operation of all integers will be a integer so get output in floating point number use 3.0 or 10.0 or both