Why ans 0 in %d and not 10?

Question

#include <stdio.h>

int main() {
float average;
int total = 7;
int count = 2;
float he = 3.5;

average = total / count*he;

printf("%d and %f", average, average );

return 0;
}

//why ans 0 in %d and 10.500000 in %f
https://code.sololearn.com/ccLMAC9JGh3f/?ref=app

Answer 1

Normally, when you work with floats and ints, the compiler does conversions automatically. However, with printf, the compiler does not know what type the function expects, so it leaves it as a float, when it should be an integer.

To solve this, you have to explicitly convert it to an int.

Answer 2

Because the first parameter expects explicit type conversion integer to float 🤔

Answer 3

Because printf expects an integer, but you give it a float.
https://code.sololearn.com/cZk8Bd9oPFvP/?ref=app

Answer 4

Vlad Serbu can you elaborate I can't understand you.

Answer 5

Panpan quququ pananabanana yo to yo eh