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In java what does it mean by operators associativity?

In java, according to my textbook, operators follow a specific type of associativity, for example: Operators *,/,% have associativity L to R. While, Operators +, - have associativity R to L. I have no idea about what does it mean.

11th Nov 2018, 12:32 PM
scientist
scientist - avatar
5 Answers
+ 13
SOLO FREAK try mine given examples on code-playground of java //yeah ,above information is correct , might typo error in your book[no doubt] //btw there is something called "Precedence" also & using it along with "Associativity" means U will never be confused in output of any expression ☺
11th Nov 2018, 2:58 PM
Gaurav Agrawal
Gaurav Agrawal - avatar
+ 20
operators with associativity from left to right : *,/,%,+,-,logical operators(&&,||) ,equality operators(==,!=),bitwise operators(&,^,|), shift operator(>>,>>>,<<) etc example : int y=9/3/3; //here it can be treated as (9/3)/3 =1 , not 9/(3/3) =9 because associativity of / operator is from left to right operators with associativity from right to left : assignment operator (=, +=,%=,^= etc), ternary operators(? :),cast operator(( )),new operator etc example : int b=1;c=2; int a=b=c; //a will be 2 , not 1 because it can be treated as int a=(b=c); as assignment operator(=) have precedence from right to left operators with no associativity : relational operators(>,<,<= etc) , unary post increment-decrement operator(x++,x--) are non-associative example - x++--; // will be non-associative & will cause error boolean bol=(a<b<c); //it is also invalid [very helpful information, it is from a lesson I made (might pending) ☺] //👍
11th Nov 2018, 1:17 PM
Gaurav Agrawal
Gaurav Agrawal - avatar
+ 3
Thanks Gaurav Agrawal !! Just there is still one confusion. The operators namely, relational and increment-decrement operators, are clearly non associative from your examples (which I agree with) but my textbook says they too have associativity!! here what's written in it: Relational operators have L to R associativity and increment-decre ment operators have R to L associativity what do you think? Personally I still think you are correct, but still...
11th Nov 2018, 2:53 PM
scientist
scientist - avatar
+ 2
Ok
13th Nov 2018, 12:33 AM
aka47 TV
aka47 TV - avatar
+ 2
From what I understand, the direction of associativity of an operator is going to determine the order of operation in a statement containing multiple operators of the same precedence. For example, in (3 - 2 - 1 + 2), the output should be 2, because it is interpreted as (((3 - 2) - 1) + 2), with L to R associativity. If it were the other way around, the equation would become (3 - (2 - (1 + 2))) and would evaluate to 4.
13th Nov 2018, 3:26 AM
PaintingJo
PaintingJo - avatar