Illegal C++ expression accepted by C++ Code Playground | Sololearn: Learn to code for FREE!
New course! Every coder should learn Generative AI!
Try a free lesson
0

Illegal C++ expression accepted by C++ Code Playground

Surprised by this lesson :" 55+15 // legal C++ expression //Both operands of the + operator are integers 55 + "John" // illegal // The + operator is not defined for integer and string" yet last time the C++ Code Playground seemed to accept mixted integer and string in Conditionnal & Loops the if statment exercices : int x = 5; int y = 3; if (x > y) { // here you can mix strings & integer , I ve checked it cout << "hi there"; }

20th Jun 2018, 7:46 AM
S. Kaouche
S. Kaouche - avatar
3 Answers
+ 2
So, what is the illegal thing? 55 + "John" is perfectly legal. Even if it's not a good idea. "John" is not actually a string, it's a char array. A char array is basically the same as a pointer to the beginning of the array. If you do 1 + "John" for example, you increment that pointer by 1. So now the beginning would be at index 1 and the result would be: "ohn", if you printed it. If you do 55 +"John" you increment the pointer by 55. But now it points past the allocated array and you are in the realm of undefined behaviour. But still legal C++.
20th Jun 2018, 10:41 AM
Dennis
Dennis - avatar
0
Hello Dennis , thanks for your fast reply . Please read carefully what I wrote. Have a good day !
23rd Jun 2018, 7:36 PM
S. Kaouche
S. Kaouche - avatar
0
I did read it, could you at least give us a program that shouldn't compile but does in the lesson?
23rd Jun 2018, 8:45 PM
Dennis
Dennis - avatar