Can someone help and tell me why the output of the code below is 7 ?
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function abc(a){ return(function(y) { return y+1; })
(++a)+a;
}
alert(abc(2));
You execute your function in return statement.
(function(y){
y+1;
})(++a) // ++a is an argument of your function
You execute it with ++a. Preincrementation works before going into function hence "a" is 3. Then function adds 3+1 which is 4 and then abc function returns result of inner function and adds a, so it gives 4 + 3.
