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Cout<<x endl;
0 голосов
1 ответ
#include<iostream>
using namespace std;
int main()
{
int a=10,b=20,sum=a+b;
a=5;
cout<<"The sum is\n"<< sum << endl;
9 голосов
8 ответов
Can someone help me please. I can understand the result of the cout << p << endl;
#include <iostream>
using namespace std;
int main() {
int x = 8;
int *p;
p = &x;
cout << *p << endl;
cout << p << endl;
cout << &p;
return 0;
}
1 голос
6 ответов
int passenger, seats, filledseats, emptyseats; seats=50; cout << "Enter passengers amount" << endl; cin >> passenger;
-1 голос
3 ответов
Wouldn't it be more efficient to write
while(num<5){
cout << "The number is" << num << endl;
num = num + 1;
}
as
while(num<5){
cout << "The number is" << num++ << endl;
}
1 голос
2 ответов
#include <iostream>
using namespace std;
int main()
{
int a;
for ( a = 10; a <= 100; a+=10){
cout << a << endl;
8 голосов
5 ответовIn the code cout<< "places selected" << places << endl; only shows the last letter that the user enter. Do you guys know how ?
1 голос
6 ответов
int main () {
for (int x = 1; x <= 10; x++) {
cout << 1 + (rand() % 6) << endl;
}
}
0 голосов
6 ответов
int num = 1;
int number;
int total = 0;
while (num <= 5) {
cin >> number;
total += number;
num++;
}
cout << total << endl;
0 голосов
8 ответов
#include <iostream>
using namespace std;
int sum(int a, int b=42) {
int result = a + b;
return (result);
}
int main() {
int x = 24;
int y = 36;
//calling the function with both parameters
int result = sum(x, y);
cout << result << endl;
//calling the function without b
result = sum(x);
cout << result << endl;
return 0;
}
why is da last function cout 66 and not 48 isn't it suppose to add 24+24?
1 голос
6 ответов
wt is output if a=2.0,b=2.5
#include <iostream>
using namespace std;
int main()
{
int a, b;
int sum;
cout << "Enter a number \n";
cin >> a;
cout << "Enter another number \n";
cin >> b;
sum = a + b;
cout << "Sum is: " << sum << endl;
return 0;
}
0 голосов
21 ответ
double arr[]={5,2,7,8,11,9};
int n = sizeof(arr) / sizeof(arr[0]);
double sum = 0;
for(int i=0;i<n;i++)
{
sum+= arr[i];
}
double avg = sum / n;
cout<< "avarage ="<< avg<< endl;
return 0;
)
/*what does int n= sizeof(arr[]) /sizeof(arr[0]);
do, can someone explain that line for me*/
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3 ответов
in the following why the code num=num+1;can't be applied just after while loop in the beginning of curly braces?
#include <iostream>
using namespace std;
int main()
{
int num = 1;
while (num < 6) {
cout << "Number: " << num << endl;
num = num + 1;
}
return 0;
}
0 голосов
7 ответов
int main()
{
int num = 1;
int number;
int total = 0;
while (num <= 5) {
cin >> number;
total += number;
num++;
}
cout << total << endl;
return 0;
}
i neeed a very simple discussion please about the loop i don't understand anything
1 голос
3 ответов
what is tjis code problem!
#include <iostream>
using namespace std;
int main()
{
int b = 5;
int arr[b] = {11, 35, 62, 555, 989};
int sum = 0;
for (int x = 0; x < 5; x++) {
sum += arr[x];
}
cout << sum << endl;
return 0;
}
I cannot make an array using int variable in order to define array's element number!?
1 голос
7 ответов
what will be output??
#include <iostream>
using namespace std;
int main(int a)
{
cout << a << "\n";
return 0;
}
int main(char *a)
{
cout << a << endl;
return 0;
}
int main(int a, int b)
{
cout << a << " " << b;
return 0;
}
int main()
{
main(3);
main("Subodh");
main(9, 6);
return 0;
}
if output is compilation compilation error then how can we overload "main" function in C++
0 голосов
5 ответов
Wher is mistake?
0 голосов
5 ответов
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