0

# Elif — Leap Year Practice

What did I do wrong ? #5 and #6 case didn’t check through year = int(input()) if year % 4 : print("Leap year") elif year % 100 : print("Leap year") elif year % 400 : print("Not a leap year") else : print("Leap year")

1st Feb 2021, 10:03 PM
Davon
3 ответов
+ 5
Firstly, you need to remember that if you say year % 4, you will get the remainder of the operation. If you wanted to know if the number is divisible by 4, you should do year % 4 == 0 to know if there was not a remainder. Secondly, when the if statement checks if it is divisible by 100, it will output "Not leap year" and then the program would be over omitting the part when it checks if it is divisible by 400. A better approach to your problem would be the following: year = int(input()) condition1 = year % 4 == 0 #This variable will be True if the year is divisible to 4 condition2 = not year % 100 == 0 or year % 400 == 0 #This variable will be True if the year is not divisible by 100 or if the year is divisible by 400 if condition1 and condition2: print("Leap year") else: print("Not leap year") #If both conditions are true, output Leap year, otherwise output Not leap year
1st Feb 2021, 10:30 PM
Paula Campbell
+ 2
According to the following article , https://docs.microsoft.com/en-us/office/troubleshoot/excel/determine-a-leap-year It seems like you need to check first, if year %100 and year%400 ,then leap year elif year%4 ,then leap year else not leap year.
1st Feb 2021, 10:29 PM
Abhay
0
Pls someone help paste the leap year question here.
15th May 2021, 9:47 PM
Samuel Mbah
Актуальное сегодня
super laggy