What is the problem in the code

Question

Let's use exponentiation to solve a known problem.
You are offered a choice of either $1.000.000 or $0.01 (one penny) doubled every day for 30 days (the resulting amount is doubled every day).

Task:
Write a program to calculate the amount that will result from the doubling to understand which choice results in a larger amount.

"""""
v = 0.01 *(2**30)
r = 1*(2**30)
if v >= r:
print(v)
else:
print(r)
"""""

When i run it the output is 1073741828 but it shows as 10737418.28 but how it is possible. Am i missing something please explain.

Answer 1

where's your code tho? we don't see what you're thinking inside the brain.

Answer 2

You need calculate only 1 cent doubled every day during the 30 days and print result, read the problem condition carefully

Answer 3

if v<=r:
by the way, if you just print the value of v your code will work fine.
No need to declare r.

Answer 4

You need to print only 0.01 * (2 ** 30)

Answer 5

Sebastián ok I understood I was confused because of . I think there should be a comma instead of dot in million. Thanks for telling

Answer 6

I'm still a bit confused but I will get there, please tell me if I need to know something.

Answer 7

The one between the """" """"

Answer 8

Zatch bell but question said print larger amount so why v<= r . if i am missing something please explain

Answer 9

Roma Butaku but why the code said you are provided a choice and calculate the results in larger amount

Answer 10

What is the meaning of 1.000.000 here

Answer 11

As Roma Bataku said, you should read the problem more carefully. It says you must choose $ 1million or $ 0.01 that doubles each day by 30 days. No need to calculate 1*(2**30).

Answer 12

v = 0.01 *(2**30)
r = 1*(2**30)
if v <= r:
print(v)
else:
print(r)