Discussões Q&A
>= 18?
0 Voto
4 Respostas
>= invalid syntax
-1 Voto
3 Respostas
What means =< or >=
0 Voto
4 Respostas
meaning of this >=
0 Voto
3 Respostas
def max3bad(x,y,z): maximum = 0 if x >= y: if x >= z: maximum = x elif y >= z: maximum = y else: maximum = z return(maximum)
-1 Voto
1 Resposta
i = 0
while 1==1:
print(i)
i = i + 1
if i >= 5:
print("Breaking")
print("Finished")
break
0 Voto
10 Respostas
Python question, in python3 this two symbols i don't understand (<= , >= ) please give me examples and explain also.
1 Voto
3 Respostas
weight = flaot(input())
height = flaot(input())
bmi = weight/(height**2)
if bmi < 18.5:
print('underweight')
elif (bmi >= 1
-1 Voto
3 Respostas
How can get the code in java script to print true or false when using === == <= >= e.t.c.
-2 Votos
8 Respostas
i = 0
while 1==1:
print(i)
i = i + 1
if i >= 5:
print("Breaking")
break
print("Finished")
1 Voto
3 Respostas
age = int(input())
if(age == 0 and age <= 11):
print('Child')
elif(age >= 11 and age <= 17):
print('Teen')
elif(age > 17
0 Voto
3 Respostas
the integer temperature in Celsius as input and output "Boiling" if the temperature is >= 100.Output "Not boiling" if not''
0 Voto
2 Respostas
weight = input()
height = input()
BMI = weight / (height ** 2)
if BMI < 18.5:
print(Underweight)
elif BMI >= 18.5 and BM
2 Votos
4 Respostas
int num = 2;
int x = 3;
if(num >= 2) {
if(x > 4) { num = 3; }
else { num = 4; }
}
else {x = 1; }
1 Voto
11 Respostas
What is the value of f(255) for the function below?def f(x): d=0 while x >= 1: (x,d) = (x/4,d+1) return(d)
0 Voto
1 Resposta
using BETWEEN and >= AND <= are the same right? the BETWEEN operator includes the values listed and everything between them, yes?
-1 Voto
3 Respostas
double Max = 12.7;
if (Max >= 12)
System.out.print("FRENCH"); else
System.out.print("FRIES");
Can the code be converted to Switch ?
If yes why ?
If no why?
1 Voto
2 Respostas
Hi, I need assistance aka HELP!
I've done this calculation in various ways some of printed nothing but zeros non stop.
Using while loop calculate all numbers 1 to 1000 add numbers to sum = sum + i
int sum = 0;
// use a while loop to calculate the sum of 1 to 1000
While(int sum = 0; sum >= 1000; sum = sum + I){
System.out.println(sum);
}
0 Voto
4 Respostas
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