How can you find whether a number is odd or even in a different way(other than (x%2==0))?

Question

The main aim of this question is to find different unknown logics to find numbers are even or not!!

Answer 1

Is this a question or a challenge?

The challenge has been posed before:
https://www.sololearn.com/post/1723667/?ref=app

Answer 2

# Using the bitwise AND operator (&)
# The least significant bit (rightmost bit) of an even number is always 0.
# The least significant bit of an odd number is always 1.
# Performing a bitwise AND with 1 isolates this last bit.
if (value & 1) == 0:
print(f"'{value}' is an EVEN integer.")
else:
print(f"'{value}' is an ODD integer.")

Answer 3

if (value//2)*2 == value:
print("Even")
else:
print("Odd")