Threads

Question

Why won’t this output in the right order?

import java.lang.*;

class Main {
public static void main(String[ ] args) {
Name name = new Name();
//set priority
name.setPriority(1);

Welcome welcome = new Welcome();
//set priority
welcome.setPriority(10);

name.start();
welcome.start();
}
}

//extend the Thread class
class Welcome extends Thread{
public void run() {
System.out.println("Welcome!");
}
}

//extend the Thread class
class Name extends Thread{
public void run() {
System.out.println("Please enter your name");
}
}
https://code.sololearn.com/cn8jpBukX7H2/?ref=app

Answer 1

For simple operations don't rely on threads.. It depends on os support.. Once look at this : hope it helps.. Roderick Davis
https://www.sololearn.com/Discuss/2211828/?ref=app

Answer 2

make sure the thread priority number should be same and manipulate the function here i kept the priority number same as 5 for safe limits and i changes the function calling like in question name came first then welcome but i change it into welcome first and then the name function call and the program run smoothly.

import java.lang.*;

class Main {
public static void main(String[ ] args) {
Name name = new Name();
//set priority
name.setPriority(5);

Welcome welcome = new Welcome();
//set priority
welcome.setPriority(5);

welcome.start();
name.start();
}
}

//extend the Thread class
class Welcome extends Thread{
public void run() {
System.out.println("Welcome!");
}
}

//extend the Thread class
class Name extends Thread{
public void run() {
System.out.println("Please enter your name");
}
}

Answer 3

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class Main {
public static void main(String[ ] args) {
Name name = new Name();
name.setPriority(1);
Welcome welcome = new Welcome();
welcome.setPriority(2);
name.start();
welcome.start();
}
}
class Welcome extends Thread{
public void run() {
System.out.println("Welcome!");
}
}
class Name extends Thread{
public void run() {
System.out.println("Please enter your name");
}
}

Answer 4

Jayakrishna🇮🇳 this is a soloLearn problem then. Thanks.

Answer 5

class Main {
public static void main(String[ ] args) {
Name name = new Name();
name.setPriority(1);
Welcome welcome = new Welcome();
welcome.setPriority(2);
name.start();
welcome.start();
}
}
class Welcome extends Thread{
public void run() {
System.out.println("Please enter your name");

}
}
class Name extends Thread{
public void run() {
System.out.println("Welcome!");
}
}

Answer 6

Jayakrishna🇮🇳
The question:

We are writing a registration program for our app. At first it should welcome the users, then ask the users to enter their names.
But program you are given executes this sequence in reverse order.
Complete the program by extending the Thread class for Welcome and Name classes, then setting priorities for their run methods so that the program outputs the messages in the correct order.

Answer 7

I don’t know what’s wrong so I switched these statements
welcome.start();
name.start();
To get a good result.
This is not the way but
My code doesn’t work

Answer 8

عع

Answer 9

What's your correct order of thinking? Can you elaborate it more?

Edit : Roderick Davis am getting output :

please enter your name
Welcome

Answer 10

Jayakrishna🇮🇳 Same problem to me...

https://www.sololearn.com/Discuss/2672570/?ref=app

Answer 11

class Main {
public static void main(String[ ] args) {
Name name = new Name();
//set priority
name.setPriority(1);

Welcome welcome = new Welcome();
//set priority
welcome.setPriority(10);

name.start();
welcome.start();
}
}

//extend the Thread class
class Welcome extends Thread{
public void run() {
System.out.println("Welcome!");

}
}

//extend the Thread class
class Name extends Thread{
public void run() {
System.out.println("Please enter your name");

}

}