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How to use if and else conditions while dealing list data?
numbers = [13, 5102, 45, 2301.40, 203, 1502, 3] 1. Set the value of the variable numbers_sum to be the sum of all the numbers in the list numbers. 2. By using a built-in function, complete the ifstatement. If our list has at least one member, we want to print the mean; otherwise, we want to print the number 0.
11 Respostas
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Did it worked??
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To check if list numbers has elements, you can also use: if numbers:
Here is the sample:
numbers = [13, 5102, 45, 2301.40, 203, 1502, 3]
if numbers:
print(sum(numbers)/len(numbers))
else:
print("0")
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and you can use sum function to find out the sum of numbers in the list
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your first if statement shoulf be:
if len(numbers):
# all it wants is for you to check if the list is empty
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Try using print(0) instead of print("0")
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Hi Akshay,
I tried with that option as well but not passed the test case
1. numbers = [13, 5102, 45, 2301.40, 203, 1502, 3]
2. number_sum=sum(numbers)
if (numbers_sum)>= 1 :
print(numbers_sum/len(numbers))
else:
print("0")
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Thanks Akshay,
final code as follows
if len(numbers)>= 1 :
print(numbers_sum/len(numbers))
else:
print(0)
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Hi Akshay,
Yes it worked at last.
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use a loop to loop through the list.
use if amd elif statements to check things
print out what yod like.
please show an attempt
0
Hi Lothar, Akshya, Slick,
Thanks for your prompt replies but none of them are fix the issue as I mentioned earlier we need to verify the list total is greater than 1 or not first if yes then only we need to print mean of the listed values else print as "0" so please explain what did I miss in my attempt?
if (numbers_sum)>= 1 :
print(numbers_sum/len(numbers))
else:
print("0")