Is this an infinite loop?

Question

Explain !!!.... unsigned int means only positive values right
Please explain 🤔🤔🤔🤔

https://code.sololearn.com/cd9qc0I2NRXv/?ref=app

Answer 1

Unsigned meaning positive value only so when we do i-- it will take the value on other side of range which is always positive or equal to zero so the condition will get always satisfied and the loop will run infinite times

Answer 2

Yes, due to unsigned integer overflow. When subtracting from 0 with a unsigned int the result overflows back to the upper limit of an unsigned int. Where unsigned int range is 0-Max, 0 - 1 = Max.
Try the following code

unsigned int a = 0;
a--;
printf("%u", a);

Answer 3

Try yourself!
Instead of printing "a" just printf("%x ", i)
What happens?
Instead of evolving from 0 to -1, i evolves from 0 to ffffffff...
In the signed case, ffffffff is by convention taken as -1 and the loop stops.
In the unsigned case, i will never be considered negative and the loop will never stop.

Answer 4

Thk u

Answer 5

Thk u Aayushi 😍💙