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why cout << i==ā1ā causes an error?
https://code.sololearn.com/c6wLOPzA10dY/?ref=app In this code: Int i=5; cout << i==ā1ā Causes an error However, cout << (i==ā1ā) Prints 0?
3 Respostas
+ 9
The overloaded insertion << operator has higher precendence over == operator.
+ 5
i see, now it makes sense, it would be nice if << operator was explained in advanced c++ tutorial
0
yes