Make a program in which If the no. Is even then divide by 3 and when the no is odd then multiply by 7

Answer 1

on what language?

well the steps are:
first you input the variable (x), then use the mod function,
if x mod 2 = 0 then divide x with 3
else multiply x with 7
then you return the result

edit: misread the question

Answer 2

in c++

Answer 3

thanks

Answer 4

#include <iostream>
using namespace std;

int main() {
int x;
cin >>x;
if (x%2 == 0) {
x = x / 3;
} else {
x = x * 7;
}
cout << x;
}