Can anyone provide the code of this simple problem in c++

Question

You are working on a ticketing system. A ticket costs $10.
The office is running a discount campaign: each group of 5 people is getting a discount, which is determined by the age of the youngest person in the group.
You need to create a program that takes the ages of all 5 people as input and outputs the total price of the tickets.

Sample Input:
55
28
15
38
63

Sample Output:
42.5

The youngest age is 15, so the group gets a 15% discount from the total price, which is $50 - 15% = $42.5

Answer 1

#include <iostream>
using namespace std;

int main() {
int ages[5];

for (int i = 0; i < 5; ++i) {
cin >> ages[i];
}
//your code goes here
float m,l;
l=ages[0];
for( int x=0;x<5;x++){
if(l>ages[x]){
l=ages[x];
}
}
m=(float)(l*50)/100;
cout<<50-m;
return 0;
}

Answer 2

#include <iostream>
using namespace std;

int main() {
int l,a[5];

for (int i = 0; i < 5; ++i) {
cin >> a[i];
}
//your code goes here
if(a[0] < a[1] && a[0] < a[2] && a[0] < a[3] && a[0] < a[4]){
l=a[0];
}
if(a[1] < a[0] && a[1] < a[2] && a[1] < a[3] && a[1] < a[4]){
l=a[1];}
else if(a[2] < a[0] && a[2] < a[1] && a[2] < a[3] && a[2] < a[4]){
l=a[2];}
else if(a[3] < a[0] && a[3] < a[2] && a[3] < a[1] && a[3] < a[4]){
l=a[3];}
else if(a[4] < a[0] && a[4] < a[1] && a[4] < a[2] && a[4] < a[3]){
l=a[4];}
float m=(float)(l*50)/100;
float j=50-m;
cout<<j;

return 0;
}